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AP EAMCET · Maths · Application of Derivatives

Let \(\mathrm{f}: \mathbb{R} \rightarrow \mathbb{R}\) be a continuous function. If \(\mathrm{px}+\mathrm{my}+\mathrm{n}=0\) is a tangent drawn to the curve \(y=f(x)\) at \(x=\alpha\), then at \(x\) \(=0, \frac{d}{d x}\left(f\left(\alpha e^{2 x}\right)\right)=\)

  1. A \(0\)
  2. B \(\frac{\mathrm{p}}{\mathrm{m}}\)
  3. C \(\frac{-2 \alpha m}{p}\)
  4. D \(\frac{-2 p \alpha}{m}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{-2 p \alpha}{m}\)

Step-by-step Solution

Detailed explanation

Since \(p x+m y+n=0\) is tangent drawn to the curve \(y=f(x)\) at \(x=\alpha\). Hence \(\frac{d y}{d x}=f^{\prime}(x)=(\) Slope of \(p x+m y+n=0)\) \[ \Rightarrow \quad \frac{d f(\mathrm{x})}{d x}=\left(\frac{-p}{m}\right) \Rightarrow f(x)=\frac{-p}{m} x+c \] when…