AP EAMCET · Maths · Circle
If \((1,3)\) is the midpoint of a chord of the circle, \(x^2+y^2-4 x-8 y+16=0\), then the area of the triangle formed by that chord with the coordinate axes is
- A 16
- B 8
- C 4
- D \(8 \sqrt{2}\)
Answer & Solution
Correct Answer
(B) 8
Step-by-step Solution
Detailed explanation
Circle : \(x^2+y^2-4 x-8 y+16=0\) Equation of chord with given middle point \((1,3)\) is \(\begin{aligned} & T=S_1 \Rightarrow x+3 y-2(x+1)-4(y+3)+16 \\ & =1+9-4-24+16 \\ & \Rightarrow x+y=4 \end{aligned}\) It cuts co-ordinate axes at \(A(0,4)\) and \(B(4,0)\)…
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