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AP EAMCET · PHYSICS · Laws of Motion

A 30 kg slab B rests on a frictionless floor as shown in the figure. A 10 kg block A rests on top of the slab- B. The coefficients of static and kinetic friction between the block A and the slab B are 0.60 and 0.40 respectively. When block-A is acted upon by a horizontal force of 100 N, as shown, find the resulting acceleration of the slab- B. g=9.8 m s-2

  1. A 0.98 m s-2
  2. B 1.47 m s-2
  3. C 1.52 m s-2
  4. D 1.31 m s-2
Verified Solution

Answer & Solution

Correct Answer

(D) 1.31 m s-2

Step-by-step Solution

Detailed explanation

The maximum frictional force, μsN=0.6×10×9.8=58 N As the frictional force is less than the applied force, the block and slab won't move together. For the block, f=μmg=0.4×10×0.98 ⇒f=39.2 N The slab moves due to the kinetic friction.…
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