AP EAMCET · PHYSICS · Work Power Energy
Consider the following statements \(A\) and \(B\) identify the correct answer given below :
(A) A body initially at rest is acted upon by a constant force. The rate of change of its kinetic energy varies linearly with time
(B) When a body is at rest, it must be in equilibrium.
- A \(A\) and \(B\) are correct
- B \(A\) and \(B\) are wrong
- C \(A\) is correct and \(B\) is wrong
- D \(A\) is wrong and \(B\) is correct
Answer & Solution
Correct Answer
(C) \(A\) is correct and \(B\) is wrong
Step-by-step Solution
Detailed explanation
\(\mathrm{KE}=\frac{1}{2} m v^2=\frac{1}{2} m(a t)^2=\frac{1}{2} m a^2 t^2\) Rate of change of KE, \(\frac{d K}{d t}=\frac{d}{d t}\left(\frac{1}{2} m a^2 t^2\right)=m a^2 t\) \(\therefore \quad \frac{d K}{d t} \propto t\) So, statement \(A\) is correct. When the body is at rest,…
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