AP EAMCET · PHYSICS · Alternating Current
A \(100 \mu \mathrm{F}\) capacitor is connected to a \(100 \mathrm{~V}\), \(50 \mathrm{~Hz}\) AC supply. The rms value of the current is
- A \(3.14 \mathrm{~A}\)
- B \(4.75 \mathrm{~A}\)
- C \(2.33 \mathrm{~A}\)
- D \(5.5 \mathrm{~A}\)
Answer & Solution
Correct Answer
(A) \(3.14 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Given, \(V_{\mathrm{rms}}=100 \mathrm{~V}, f=50 \mathrm{~Hz}\) \(C_1=100 \mu \mathrm{F}=100 \times 10^{-6} \mathrm{~F}\) Now, reactance of capacitor, \(X_C=\frac{1}{C \omega}=\frac{1}{C \times 2 \pi f}\)…
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