AP EAMCET · Maths · Vector Algebra
\(\bar{a}, \bar{b}, \bar{c}\) are unit vectors. If \(\bar{a}, \bar{b}\) are perpendicular vectors, \((\bar{a}-\bar{c}) \cdot(\bar{b}+\bar{c})=0\) and \(\overline{\mathrm{c}}=l \overline{\mathrm{a}}+\mathrm{m} \overline{\mathrm{b}}+\mathrm{n}(\overline{\mathrm{a}} \times \overline{\mathrm{b}}) ;\left(l, \mathrm{~m}, \mathrm{n}\right.\) are scalars), then \(\mathrm{n}^2=\)
- A \(l^2+\mathrm{m}^2\)
- B \(-2 l \mathrm{~m}\)
- C \(2 l-2 \mathrm{~m}\)
- D \(l \mathrm{~m}+l+\mathrm{m}\)
Answer & Solution
Correct Answer
(B) \(-2 l \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\((\bar{a}-\bar{c}) \cdot(\bar{b}+\bar{c})=0 \Rightarrow \bar{a} \cdot \bar{b} + \bar{a} \cdot \bar{c} - \bar{b} \cdot \bar{c} - \bar{c} \cdot \bar{c} = 0\)…
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