AP EAMCET · Maths · Pair of Lines
The distance between the parallel lines \(9 x^2-6 x y+y^2+18 x-6 y+8=0\) is
- A \(\sqrt{10}\)
- B 2
- C \(\frac{2 \sqrt{153}}{\sqrt{10}}\)
- D \(\frac{2}{\sqrt{10}}\)
Answer & Solution
Correct Answer
(D) \(\frac{2}{\sqrt{10}}\)
Step-by-step Solution
Detailed explanation
\((3x-y)^2 + 6(3x-y) + 8 = 0\) \((3x-y+2)(3x-y+4) = 0\) \(d = \frac{|C_1 - C_2|}{\sqrt{A^2 + B^2}} = \frac{|2 - 4|}{\sqrt{3^2 + (-1)^2}}\) \(d = \frac{2}{\sqrt{10}}\)
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