AP EAMCET · Maths · Indefinite Integration
\(\int\left[\log (\log x)+\frac{1}{(\log x)^2}\right] d x=\)
- A \(x[\log (\log x)+\log x]+c\)
- B \(\frac{x}{\log (\log x)}+c\)
- C \(x \log (\log x)+c\)
- D \(x\left[\log (\log x)-\frac{1}{\log x}\right]+c\)
Answer & Solution
Correct Answer
(D) \(x\left[\log (\log x)-\frac{1}{\log x}\right]+c\)
Step-by-step Solution
Detailed explanation
\(I=\int\left[\log (\log x)+\frac{1}{(\log x)^2}\right] d x\) Let, \(\log x=t \Rightarrow d x=e^t d t\) \(\therefore \quad I=\int e^t\left(\log (t)+\frac{1}{t^2}\right) d t\)…
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