AP EAMCET · Maths · Permutation Combination
Eight different letters of an alphabet are given. Words of four letters from these are formed. The number of such words with at least one letter repeated is :
- A \(\left(\begin{array}{l}8 \\ 4\end{array}\right)-{ }^8 P_4\)
- B \(8^4+\left(\begin{array}{l}8 \\ 4\end{array}\right)\)
- C \(8^4-{ }^8 P_4\)
- D \(8^4-\left(\begin{array}{l}8 \\ 4\end{array}\right)\)
Answer & Solution
Correct Answer
(C) \(8^4-{ }^8 P_4\)
Step-by-step Solution
Detailed explanation
Total number of words formed by 4 letters given from eight different letters with repetition \(=8^4\) and number of words with no repetition \(={ }^8 P_4\) \(\therefore \quad\) Required number of words \(=8^4-{ }^8 P_4\)
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