AP EAMCET · Maths · Permutation Combination
The number of ways is which 6 men and 5 women can dine at a round table, if no two women are to sit together is
- A \(6 ! \times 5\) !
- B 30
- C \(5 ! \times 4\) !
- D \(7 ! \times 5\) !
Answer & Solution
Correct Answer
(A) \(6 ! \times 5\) !
Step-by-step Solution
Detailed explanation
6 men can be seated in 5 ! ways \([\because\) Number of ways in round table \(=(n-1) !]\) Number of ways of placing women in between 6 men \(=6 p_5=6\) ! Total number of ways \(=5 ! \times 6 !\)
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