AP EAMCET · Maths · Limits
\(\lim _{x \rightarrow 0} \frac{4^x-9^x}{x\left(4^x+9^x\right)}\) is equal to
- A \(\log \frac{2}{3}\)
- B \(\log \frac{3}{2}\)
- C \(\frac{1}{2} \log \frac{2}{3}\)
- D \(\frac{1}{2} \log \frac{3}{2}\)
Answer & Solution
Correct Answer
(A) \(\log \frac{2}{3}\)
Step-by-step Solution
Detailed explanation
We have, \[ \lim _{x \rightarrow 0} \frac{4^x-9^x}{x\left(4^x+9^x\right)} \] Using L-Hospital's rule…
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