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AP EAMCET · Maths · Vector Algebra

In a trapezium \(A B C D, \mathbf{B C}=\lambda \mathbf{A D}\) and \(\mathbf{x}=\mathbf{A C}+\mathbf{B D}\). If \(\mathbf{x}=p \mathbf{A D}\), then \(p=\)

  1. A \(\lambda-1\)
  2. B \(\lambda+1\)
  3. C \(1-\lambda\)
  4. D \(2 \lambda-1\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\lambda+1\)

Step-by-step Solution

Detailed explanation

Let position vector of \(A, B, C\) and \(D\) are a, b, c and d, respectively.…