AP EAMCET · Maths · Matrices
If \(A\) and \(B\) are \(n \times n\) square matrices such that \((2 A+B)^2+(A-3 B)^2=5 A^2-2 A B+10 B^2\), then \(A B A B=\)
- A \(\frac{1}{2}\left[(A-B)^2+(A+B)^2\right]\)
- B \(4 A B\)
- C \(\frac{1}{2}\left[(A+B)^2-(A-B)^2\right]\)
- D \(A^2 B^2\)
Answer & Solution
Correct Answer
(D) \(A^2 B^2\)
Step-by-step Solution
Detailed explanation
Given, \((2 A+B)^2+(A-3 B)^2=5 A^2-2 A B+10 B^2\) \(\Rightarrow 4 A^2+B^2+2 A B+2 B A+A^2+9 B^2\) \(-3 A B-3 B A-5 A^2+2 A B-10 B^2=0\) \(\Rightarrow \quad A B-B A=0 \Rightarrow A B=B A\) Then, \(A B A B=(A B)(A B)=(A A)(B B)=A^2 B^2\)
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