ExamBro
ExamBro
AP EAMCET · Maths · Three Dimensional Geometry

Let \(\vec{a} \times \vec{b}=7 \hat{i}-5 \hat{j}-4 \hat{k}\) and \(\vec{a}=\hat{i}+3 \hat{j}-2 \hat{k}\). If the length of projection of \(\vec{b}\) on \(\vec{a}\) is \(\frac{8}{\sqrt{14}}\), then \(|\vec{b}|=\)

  1. A \(121\)
  2. B \(\sqrt{12}\)
  3. C \(\sqrt{11}\)
  4. D \(144\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\sqrt{11}\)

Step-by-step Solution

Detailed explanation

Since, length of projection of \(\vec{b}\) on \(\vec{a}\) is \(\frac{8}{\sqrt{14}}\) \(\Rightarrow \frac{|\vec{a} \cdot \vec{b}|}{|\vec{a}|}=\frac{8}{\sqrt{14}}\) Now,…