AP EAMCET · Maths · Three Dimensional Geometry
Let \(\vec{a} \times \vec{b}=7 \hat{i}-5 \hat{j}-4 \hat{k}\) and \(\vec{a}=\hat{i}+3 \hat{j}-2 \hat{k}\). If the length of projection of \(\vec{b}\) on \(\vec{a}\) is \(\frac{8}{\sqrt{14}}\), then \(|\vec{b}|=\)
- A \(121\)
- B \(\sqrt{12}\)
- C \(\sqrt{11}\)
- D \(144\)
Answer & Solution
Correct Answer
(C) \(\sqrt{11}\)
Step-by-step Solution
Detailed explanation
Since, length of projection of \(\vec{b}\) on \(\vec{a}\) is \(\frac{8}{\sqrt{14}}\) \(\Rightarrow \frac{|\vec{a} \cdot \vec{b}|}{|\vec{a}|}=\frac{8}{\sqrt{14}}\) Now,…
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