AP EAMCET · PHYSICS · Kinetic Theory of Gases
The ratio of kinetic energy of a diatomic gas molecule at a high temperature to that of NTP is
- A \(\frac{3}{2}\)
- B \(\frac{5}{3}\)
- C \(\frac{5}{7}\)
- D \(\frac{7}{5}\)
Answer & Solution
Correct Answer
(D) \(\frac{7}{5}\)
Step-by-step Solution
Detailed explanation
The kinetic energy of a gas molecule is \(\mathrm{K}=\mathrm{K} \cdot \mathrm{E} / \text { molecule }=\frac{\mathrm{f}}{2} \mathrm{k}_{\mathrm{B}} \mathrm{~T}\) For diatomic gas, \(f_1=7\) (At high temperature) \(\mathrm{f}_2=5\) (At low temperature)…
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