AP EAMCET · Maths · Probability
Two numbers are chosen at random from \(\{1,2,3,4,5,6,7,8\}\) at a time. The probability that smaller of the two numbers is less than 4 is
- A \(\frac{7}{14}\)
- B \(\frac{8}{14}\)
- C \(\frac{9}{14}\)
- D \(\frac{10}{14}\)
Answer & Solution
Correct Answer
(C) \(\frac{9}{14}\)
Step-by-step Solution
Detailed explanation
Case I When smaller of the two numbers is 1. Then, total number of cases \[ =1 \times{ }^7 C_1=7 \] Case II When smaller of two numbers is 2 . Then, total number of cases \[ =1 \times{ }^6 C_1=6 \] Case III When smaller of two numbers is 3 . Then, total number of cases…
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- \[
\text { }\left[\begin{array}{ccc}
1 & 2 & 3 \\
-1 & 1 & 2 \\
3 & 0 & 2
\end{array}\right]
\]
\[
\left|\begin{array}{ll}
2022 & 2024 \\
2021 & 2023
\end{array}\right|
\]
is equal toAP EAMCET 2021 Hard