AP EAMCET · Chemistry · States of Matter
At \(27^{\circ} \mathrm{C}\), a closed vessel contains a mixture of equal weights of helium (mol. wt. =4), methane (mol, wt. =16) and sulphur dioxide (mol. wt. = 64). The pressure exerted by the mixture is \(210 \mathrm{~mm}\). If the partial pressures of helium, methane and sulphur dioxide are \(p_1, p_1\) and \(p_3\) respectively, which one of the following is correct?
- A \(p_3>p_2>p_1\)
- B \(p_1>p_2>p_3\)
- C \(p_1>p_3>p_2\)
- D \(p_2>p_3>p_1\)
Answer & Solution
Correct Answer
(B) \(p_1>p_2>p_3\)
Step-by-step Solution
Detailed explanation
Let us suppose each gas has \(64 \mathrm{~g}\) weight. \begin{array}{|c|c|c|c|c|} \hline Gases & Weight & \begin{array}{c}\text { wt./at. } \\ \text { wt. }\end{array} & \begin{array}{c}\text { No. of } \\ \text { moles }\end{array} & \begin{array}{c}\text { Partial } \\ \text {…
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