AP EAMCET · Maths · Differentiation
\(f(x)\) and \(g(x)\) are differentiable functions such that \(\frac{f(x)}{g(x)}=\) a non zero constant. If \(\frac{\mathrm{f}^{\prime}(\mathrm{x})}{\mathrm{g}^{\prime}(\mathrm{x})}=\alpha(\mathrm{x})\) and \(\left(\frac{\mathrm{f}(\mathrm{x})}{\mathrm{g}(\mathrm{x})}\right)^{\prime}=\beta(\mathrm{x})\), then \(\frac{\alpha(x)-\beta(x)}{\alpha(x)+\beta(x)}=\)
- A 0
- B \(f(x)+g(x)\)
- C 1
- D \(\mathrm{f}^{\prime}(\mathrm{x})+\mathrm{g}^{\prime}(\mathrm{x})\)
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {} \because \frac{\mathrm{f}^{\prime}(\mathrm{x})}{\mathrm{g}^{\prime}(\mathrm{x})}=\alpha(\mathrm{x}) \&\left(\frac{\mathrm{f}(\mathrm{x})}{\mathrm{g}(\mathrm{x})}\right)^{\prime}=\beta(\mathrm{x}) \\ & \because…
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