AP EAMCET · Maths · Probability
Two digits are selected at random from the digits 1 through 9. If their sum is even, then the probability that both are odd is
- A \(\frac{3}{8}\)
- B \(\frac{1}{2}\)
- C \(\frac{5}{8}\)
- D \(\frac{3}{4}\)
Answer & Solution
Correct Answer
(C) \(\frac{5}{8}\)
Step-by-step Solution
Detailed explanation
Let \(A=\) Getting two odd numbers \(B=\) Getting the sum as an even number. \(\therefore\) Required probability \(P(A / B)=\frac{P(A \cap B)}{P(B)}\) \(\Rightarrow P(A / B)=\frac{\frac{{ }^5 C_2}{{ }^9 C_2}}{\frac{{ }^4 C_2+{ }^5 C_2}{{ }^9 C_2}}=\frac{5}{8}\)
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