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AP EAMCET · Maths · Straight Lines

The line on which the lines \(a x+b y=1\) and \(b x+a y=1\) (with \(a \neq 0 \neq b\) ) intersect for any real values of \(a\) and \(b\) is

  1. A \(x=-y\)
  2. B \(x=2 y\)
  3. C \(2 x=y\)
  4. D \(x=y\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(x=y\)

Step-by-step Solution

Detailed explanation

Lines : \(a x+b y=1\)...(i) \(b x+a y=1\)...(ii) [Multiply Eq. (i) by \(b\) ] - [Multiply Eq. (ii) by \(a\) ] \(a b x+b^2 y-a b x-a^2 y=b-a\) \(\Rightarrow \quad y=\frac{b-a}{b^2-a^2}=\frac{1}{a+b}\) Put \(y=\frac{1}{a+b}\) in Eq. (i), \(a x=1-\frac{b}{a+b}=\frac{a}{a+b}\)…
From AP EAMCET
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