AP EAMCET · Maths · Probability
Three students \(\mathrm{X}, \mathrm{Y}\) and \(\mathrm{Z}\) appear for an examination. The probability of \(X\) passing the examination is \(\frac{1}{5}\), the probability of \(\mathrm{Y}\) passing the examination is \(\frac{1}{4}\) and the probability of \(\mathrm{Z}\) failing the examination is \(\frac{2}{3}\). The probability that atleast two of them pass the exam is
- A \(\frac{1}{6}\)
- B \(\frac{2}{5}\)
- C \(\frac{3}{4}\)
- D \(\frac{3}{5}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{6}\)
Step-by-step Solution
Detailed explanation
\(P(\) pass \()+P(\) fail \()=1\)…
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