AP EAMCET · Maths · Heights and Distances
The sum of angles of elevation of the top of a tower from two points distant \(a\) and \(b\) from the base and in the same straight line with it is \(90^{\circ}\). Then, the height of the tower is
- A \(a^2 b\)
- B \(a b^2\)
- C \(\sqrt{a b}\)
- D \(a b\)
Answer & Solution
Correct Answer
(C) \(\sqrt{a b}\)
Step-by-step Solution
Detailed explanation
Given, \(\theta+\phi=90^{\circ}\) Let the height of a tower \(=h\) Then, In \(\triangle A C P\) \(\tan \theta=\frac{h}{a}\) ...(i) In \(\triangle A B P\) \(\tan \phi=\frac{h}{b}\) ...(ii)…
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