AP EAMCET · Maths · Probability
Three numbers are chosen at random without replacement from the set \(A=\{x \in Z \mid 2 \leq x \leq 11\}\). The probability that the minimum of chosen numbers is 3 and maximum is 7 is
- A \(\frac{1}{30}\)
- B \(\frac{1}{40}\)
- C \(\frac{1}{50}\)
- D \(\frac{1}{60}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{40}\)
Step-by-step Solution
Detailed explanation
Here, \(A=\{2,3,4,5,6,7,8,9,10,11\}\) Let \(E\) be the event of choosing 3 numbers and let \(F\) be the event of choosing 3 numbers in which 3 is \(\min\) and 7 is \(\max\)…
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