AP EAMCET · Maths · Permutation Combination
Let \(S=\{0,1,2,3, \ldots, 100\}\). The number of ways of selecting \(x, y \in S\) such that \(x \neq y\) and \(x+y=100\) is
- A 51
- B 40
- C 50
- D 100
Answer & Solution
Correct Answer
(C) 50
Step-by-step Solution
Detailed explanation
Let \(S=\{0,1,2,3, \ldots, 100\} x, y \in s\). and \[ x+y=100 \] If \(x=0\), \(y=100\) \(x=1\), \(y=99\) \(x=49 \Rightarrow y=51\) In this way, the total pairs in 50 . So, the number of required ways \(=50\)
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