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AP EAMCET · Maths · Permutation Combination

Let \(S=\{0,1,2,3, \ldots, 100\}\). The number of ways of selecting \(x, y \in S\) such that \(x \neq y\) and \(x+y=100\) is

  1. A 51
  2. B 40
  3. C 50
  4. D 100
Verified Solution

Answer & Solution

Correct Answer

(C) 50

Step-by-step Solution

Detailed explanation

Let \(S=\{0,1,2,3, \ldots, 100\} x, y \in s\). and \[ x+y=100 \] If \(x=0\), \(y=100\) \(x=1\), \(y=99\) \(x=49 \Rightarrow y=51\) In this way, the total pairs in 50 . So, the number of required ways \(=50\)