AP EAMCET · PHYSICS · Laws of Motion
A spring of \(5 \times 10^3 \mathrm{Nm}^{-1}\) spring constant is stretched initially by 10 cm from unstretched position. The work required to stretch it further by another 10 cm is
- A \(75 \mathrm{~N}-\mathrm{m}\)
- B \(50 \mathrm{~N}-\mathrm{m}\)
- C \(76 \mathrm{~N}-\mathrm{m}\)
- D \(82 \mathrm{~N}-\mathrm{m}\)
Answer & Solution
Correct Answer
(A) \(75 \mathrm{~N}-\mathrm{m}\)
Step-by-step Solution
Detailed explanation
The work done required to stretch a spring from \(\mathrm{x}_1\) to \(x_2\) is \(\mathrm{W}=\frac{1}{2} \mathrm{k}\left(\mathrm{x}_2^2-\mathrm{x}_1^2\right)\)…
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