AP EAMCET · Maths · Probability
There are 3 bags \(A, B\) and \(C\). Bag \(A\) contains 2 white and 3 black balls, bag \(B\) contains 4 white and 2 black balls and Bag \(C\) contains 3 white and 2 black balls. If a ball is drawn at random from a randomly chosen bag, then the probability that the ball drawn is black, is
- A \(\frac{2}{3}\)
- B \(\frac{4}{9}\)
- C \(\frac{5}{9}\)
- D \(\frac{1}{9}\)
Answer & Solution
Correct Answer
(B) \(\frac{4}{9}\)
Step-by-step Solution
Detailed explanation
Given that \(A\) has 2 white, 3 black balls, \(B\) has 4 white and 2 black balls and \(C\) has 3 white and 2 black balls. Let event of drawing black ball from bags \(A, B\) and \[ C=\frac{1}{3} \] \(\therefore\) Required probability \(=\) Probability of black ball from bag \(A\)…
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