AP EAMCET · Chemistry · Structure of Atom
If the de Broglie wavelength of electron is \(728.14 \mathrm{~nm}\), its kinetic energy in \(\mathrm{J}\) is: (mass of electron \(=9.1 \times 10^{-31} \mathrm{~kg} ; \mathrm{h}=6.626 \times 10^{-34} \mathrm{~J} \mathrm{~s}\))
- A \(4.55 \times 10^{-25}\)
- B \(9.1 \times 10^{-25}\)
- C \(4.55 \times 10^{-23}\)
- D \(9.1 \times 10^{-23}\)
Answer & Solution
Correct Answer
(A) \(4.55 \times 10^{-25}\)
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