AP EAMCET · Maths · Quadratic Equation
The number of real values of \(m\) so that the equation \(x^2+(2 m+1) x+m=0\) has equal roots is
- A \(1\)
- B \(0\)
- C \(2\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
\(x^2+(2 m+1) x+m=0\) For equal roots, \(\begin{aligned} & \mathrm{D}=0 \\ & (2 m+1)^2-4 m=0 \\ & 4 m^2+1+4 m-4 m=0 \\ & 4 m^2+1=0 \\ & m^2=-1 / 4 \\ & m^2>0\end{aligned}\) No real values of \(m\) exist.
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