AP EAMCET · Maths · Probability
There are 2 bags each containing 3 white and 5 black balls and 4 bags each containing 6 white and 4 black balls. If a ball drawn randomly from a bag is found to be black, then the probability that this ball is from the first set of bags is
- A \(\frac{25}{57}\)
- B \(\frac{25}{41}\)
- C \(\frac{2}{5}\)
- D \(\frac{3}{5}\)
Answer & Solution
Correct Answer
(A) \(\frac{25}{57}\)
Step-by-step Solution
Detailed explanation
Let, \(B_1=\) Bags of first group, \(B_2=\) Bags of second group \(P\left(B_1\right)=\frac{2}{6}=\frac{1}{3}, P\left(B_2\right)=\frac{4}{6}=\frac{2}{3}\) and let \(B=\) the event that the ball is black…
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