AP EAMCET · Maths · Inverse Trigonometric Functions
If \(\sin x \cos h y=\cos \theta, \cos x \sin h y=\sin \theta\) and \(4 \tan x=3\). Then, \(\sin h^2 y=\)
- A \(\frac{4}{5}\)
- B \(\frac{9}{16}\)
- C \(\frac{9}{25}\)
- D \(\frac{16}{25}\)
Answer & Solution
Correct Answer
(D) \(\frac{16}{25}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {Since, } \tan x=\frac{3}{4} \\ & \Rightarrow \quad \sin ^2 x=\frac{9}{25} \\ & \text { and } \quad \cos ^2 x=\frac{16}{25} \\ & \text { and } \sin x \cosh y=\cos \theta, \cos x \sinh y=\sin \theta \\ & \because \cos ^2 \theta+\sin ^2 \theta=1 \\ &…
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