AP EAMCET · Maths · Application of Derivatives
The slope of the normal to the curve \(y=\frac{x}{x^2+1}\) at \(x=-4\) is
- A \(\frac{-289}{15}\)
- B \(\frac{-15}{16}\)
- C \(\frac{289}{15}\)
- D \(\frac{15}{16}\)
Answer & Solution
Correct Answer
(C) \(\frac{289}{15}\)
Step-by-step Solution
Detailed explanation
Slope of normal \(=-\left(\frac{d x}{d y}\right)_{\left(x_1, y_1\right)}\) Given curve, \(y=\frac{x}{1+x^2}\), then…
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