AP EAMCET · Maths · Permutation Combination
9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes. The number of ways of arranging one ball in each of the boxes is
- A \(18720\)
- B \(18270\)
- C \(17280\)
- D \(12780\)
Answer & Solution
Correct Answer
(C) \(17280\)
Step-by-step Solution
Detailed explanation
Required number of arrangements \[ \begin{aligned} & ={ }^6 P_5 \times 4 ! \\ & =720 \times 24 \\ & =17280 \end{aligned} \]
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