AP EAMCET · Maths · Inverse Trigonometric Functions
The solution of the equation \(\sin ^{-1} x+\sin ^{-1} 2 x=\frac{\pi}{3}\) is
- A \(-\frac{1}{2} \sqrt{\frac{3}{7}}\)
- B \(\frac{1}{2} \sqrt{\frac{3}{7}}\)
- C \(\frac{1}{2} \sqrt{\frac{2}{7}}\)
- D \(-\frac{1}{3} \sqrt{\frac{2}{7}}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2} \sqrt{\frac{3}{7}}\)
Step-by-step Solution
Detailed explanation
Given equation \(\sin ^{-1} x+\sin ^{-1} 2 x=\frac{\pi}{3}\) Let \(x=\sin \theta\) Then, \(\theta+\sin ^{-1}(2 \sin \theta)=\frac{\pi}{3}\)…
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