AP EAMCET · Maths · Limits
If \(n>0\) and \(\lim _{x \rightarrow 0} \frac{((a-n) n x-\tan x) \sin n x}{x^2}=0\), then minimum value of \(a\) is
- A 1
- B 2
- C 3
- D -1
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \lim _{x \rightarrow 0} \frac{((a-n) n x-\tan x) \sin n x}{x^2}=0 \\ & \lim _{x \rightarrow 0}\left[\frac{(a-n) n x-\tan x}{x}\right] \lim _{x \rightarrow 0} \frac{\sin n x}{n x} n=0 \\ & \Rightarrow n\left[\lim _{x \rightarrow 0} \frac{(a-n) n…
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