AP EAMCET · Maths · Application of Derivatives
A point on the curve \(x=3 \cos \theta, y=2 \sin \theta\) at which the tangent is perpendicular to \(X\)-axis is
- A \((3,0)\)
- B \((0,3)\)
- C \((0,-3)\)
- D \((-3,3)\)
Answer & Solution
Correct Answer
(A) \((3,0)\)
Step-by-step Solution
Detailed explanation
Given curve is \(x=3 \cos \theta, y=2 \sin \theta\) is represent ellipse, \(\frac{x^2}{9}+\frac{y^2}{4}=1\) and the tangent perpendicular to \(X\)-axis can be drawn at end points of the major axis means either at \((3,0)\) or \((-3,0)\).
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