AP EAMCET · Maths · Circle
The slope of the normal to the circle \(x^2+y^2+2 g x+2 f y\) \(+\mathrm{c}=0\) at \(\left(\mathrm{x}_1, \mathrm{y}_1\right)\) is
- A \(-\left(\frac{x_1+g}{y_1+f}\right)\)
- B \(-\left(\frac{y_1+f}{x_1+g}\right)\)
- C \(\frac{x_1+g}{y_1+f}\)
- D \(\frac{y_1+f}{x_1+g}\)
Answer & Solution
Correct Answer
(D) \(\frac{y_1+f}{x_1+g}\)
Step-by-step Solution
Detailed explanation
Given equation of circle is \[ x^2+y^2+2 g x+2 f y+c=0 \] \(\therefore\) centre \(\mathrm{c}(-\mathrm{g},-\mathrm{f})\) Slope of normal \(C P=\frac{y_1+f}{y_1+g}\)
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