AP EAMCET · Maths · Circle
The equation of the circle touching the lines \(|x-2|+|y-3|=4\) is
- A \(x^2+y^2-6 x-4 y+5=0\)
- B \(x^2+y^2-4 x-6 y+5=0\)
- C \(x^2+y^2-x-2 y-5=0\)
- D \(x^2+y^2-2 x-y-5=0\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2-4 x-6 y+5=0\)
Step-by-step Solution
Detailed explanation
Center of square: \((h, k) = (2, 3)\). Distance from center \((2, 3)\) to line \(x+y-9=0\) (one of the square's sides): \(r = \frac{|2+3-9|}{\sqrt{1^2+1^2}} = \frac{|-4|}{\sqrt{2}} = 2\sqrt{2}\). Equation of circle: \((x-h)^2 + (y-k)^2 = r^2\).…
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