AP EAMCET · Maths · Circle
Suppose a circle passes through \((0, a)\) and \((b, h)\) having its centre at \((c, 0)\). Then the value of \(c\) is
- A \(\frac{b^2-a^2+h^2}{2 b}\)
- B \(\frac{b^2+a^2-h^2}{2 b}\)
- C \(\frac{b^2-a^2+h^2}{2 a}\)
- D \(\frac{b^2+a^2-h^2}{2 a}\)
Answer & Solution
Correct Answer
(A) \(\frac{b^2-a^2+h^2}{2 b}\)
Step-by-step Solution
Detailed explanation
Let \(m\) be mid point of \(\mathrm{AB}\) Coordinates of \(\mathrm{M}\) are \(\left(\frac{0+b}{2}, \frac{a+h}{2}\right) \equiv\left(\frac{b}{2}, \frac{a+h}{2}\right)\) \(\mathrm{OA}^2=\mathrm{AM}^2+\mathrm{OM}^2\) \((\mathrm{C}-0)^2+(0-a)^2=\)…
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