AP EAMCET · Maths · Straight Lines
The sides of a triangle are \(3 x+2 y-6=0,2 x-3 y+6=0\) and \(x+2 y+2=0\). If \(P(0, b)\) lies either on the triangle or inside the triangle, then \(b\) lies in the interval
- A \([-1,3]\)
- B \([2,3]\)
- C \([-1,2]\)
- D \([-2,2]\)
Answer & Solution
Correct Answer
(C) \([-1,2]\)
Step-by-step Solution
Detailed explanation
Given \(3 x+2 y-6=0,2 x-3 y+6=0, x+2 y+2=0\) We can re-write it as follows \(\frac{x}{2}+\frac{y}{3}=1, \frac{x}{(-3)}+\frac{y}{2}=1, \frac{x}{-2}+\frac{y}{-2}=1\) \(\because \quad P \equiv(0, b)\) The triangle \(A B C\) in the above graph is the required triangle. In which,…
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