AP EAMCET · Maths · Pair of Lines
The transformed equation of \(x^2-y^2+2 x+4 y=0\) when the origin is shifted to the point \((-1,2)\) is
- A \(x^2+y^2=1\)
- B \(x^2+3 y^2=1\)
- C \(x^2-y^2+3=0\)
- D \(4 x^2+9 y^2=36\)
Answer & Solution
Correct Answer
(C) \(x^2-y^2+3=0\)
Step-by-step Solution
Detailed explanation
\(x^2-y^2+2 x+4 y=0\) Origin is shifted to \((-1,2)\), Let \(x=X-1, y=Y+2\) \(\begin{aligned} & \Rightarrow(X-1)^2-(Y+2)^2+2(X-1)+4(Y+2)=0 \\ & \Rightarrow X^2-Y^2+3=0 \end{aligned}\)
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