AP EAMCET · Maths · Circle
The radius of the circle passing through the points of intersection of the circles \(x^2+y^2+2 x+4 y+1=0, x^2+y^2-2 x-4 y-4=0\) and intersecting the circle \(x^2+y^2=6\) orthogonally is
- A \(\sqrt{19}\)
- B \(5\)
- C \(\sqrt{39}\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(\sqrt{39}\)
Step-by-step Solution
Detailed explanation
Let the required circle be \(S\). The equation of a circle passing through the intersection of \(S_1 \equiv x^2+y^2+2 x+4 y+1=0\) and \(S_2 \equiv x^2+y^2-2 x-4 y-4=0\) is \(S_1+\lambda S_2=0\). \( (x^2+y^2+2x+4y+1) + \lambda(x^2+y^2-2x-4y-4) = 0 \)…
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