AP EAMCET · Maths · Hyperbola
Let \(\mathrm{X}\) - axis be the transverse axis and \(\mathrm{Y}\)-axis be the conjugate axis of a hyperbola \(\mathrm{H}\). Let \(\mathrm{x}^2+\mathrm{y}^2=16\) be the director circle of \(\mathrm{H}\). If the perpendicular distance from the centre of \(\mathrm{H}\) to its latus rectum is \(\sqrt{34}\) then \(\mathrm{a}+\mathrm{b}=\)
- A 8
- B 9
- C 5
- D 7
Answer & Solution
Correct Answer
(A) 8
Step-by-step Solution
Detailed explanation
We have equation of the director circle of hyperbola \[ \begin{aligned} & \frac{x^2}{a^2}-\frac{y^2}{b^2}=1 \text { is } x^2+y^2=a^2-b^2 \\ & \therefore a^2-b^2=16 \end{aligned} \] We have the perpendicular distance from centre \((0,0)\) of hyperbola to its latus rectum is ae.…
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