AP EAMCET · Maths · Vector Algebra
If \(\vec{a}=t \vec{b}\) where \(t < 0\) is a scalar, then
- A \(\vec{a}, \vec{b}\) are like vectors and \(|\vec{a}|>|\vec{b}|\)
- B \(\vec{a}, \vec{b}\) are unlike vectors and \(|\vec{a}|>|\vec{b}|\)
- C \(\vec{a}, \vec{b}\) are like vectors and \(|\vec{a}| < |\vec{b}|\)
- D \(\overrightarrow{\mathrm{a}}, \overrightarrow{\mathrm{b}}\) are unlike vectors and either \(|\overrightarrow{\mathrm{a}}| \geq|\overrightarrow{\mathrm{b}}|\) or \(|\overrightarrow{\mathrm{a}}| < |\overrightarrow{\mathrm{b}}|\)
Answer & Solution
Correct Answer
(D) \(\overrightarrow{\mathrm{a}}, \overrightarrow{\mathrm{b}}\) are unlike vectors and either \(|\overrightarrow{\mathrm{a}}| \geq|\overrightarrow{\mathrm{b}}|\) or \(|\overrightarrow{\mathrm{a}}| < |\overrightarrow{\mathrm{b}}|\)
Step-by-step Solution
Detailed explanation
Given \(\vec{a}=t \vec{b}\) where \(t < 0\) is a scalar \(\therefore \mathrm{t}\) is negative. \(\Rightarrow \mathrm{t}=-\mathrm{k}\) for some \(\mathrm{k} \in \mathrm{Z}^{+}\) So, we have \(\vec{a}=-k \vec{b}\) ......(i)…
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