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AP EAMCET · Maths · Probability

The probability that A speaks truth is \(4 / 5\), while the probability that \(B\) speaks truth is \(3 / 4\). Then the probability that A and B contradict each other, when asked to reveal the fact is

  1. A \(\frac{3}{20}\)
  2. B \(\frac{1}{5}\)
  3. C \(\frac{7}{20}\)
  4. D \(\frac{4}{5}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{7}{20}\)

Step-by-step Solution

Detailed explanation

\(A=\) Event that A speaks the truth \(B=\) Event that B speaks the truth \(\begin{aligned} & P(A)=\frac{4}{5} \Rightarrow P\left(A^c\right)=\frac{1}{5} \\ & P(B)=\frac{3}{4} \Rightarrow P\left(B^c\right)=\frac{1}{4}\end{aligned}\) Now, the required probability…