AP EAMCET · Maths · Circle
For any real number \(\lambda \neq 1\), the centre of the circle that passes through \(\mathrm{A}(1, \lambda), \mathrm{B}(\lambda, 1)\) and \((\lambda, \lambda)\) is
- A \(\left(\frac{1+\lambda}{2}, \frac{1+\lambda}{2}\right)\)
- B \(\left(\frac{1+2 \lambda}{3}, \frac{1+2 \lambda}{3}\right)\)
- C \((1+2 \lambda, 1+2 \lambda)\)
- D \(\left(\frac{\lambda}{2}, \frac{\lambda}{2}\right)\)
Answer & Solution
Correct Answer
(D) \(\left(\frac{\lambda}{2}, \frac{\lambda}{2}\right)\)
Step-by-step Solution
Detailed explanation
Let circles passes through \(\mathrm{A}(1, \lambda),(\mathrm{BC} \lambda, 1)\) and \(\mathrm{C}(\lambda, \lambda)\) hence, equation of circle are…
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