AP EAMCET · Maths · Limits
\(\lim _{n \rightarrow \infty}\left\{n-\sqrt{n^2-4 n}\right\}=\)
- A 0
- B 2
- C 4
- D 1
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
\( \lim _{n \rightarrow \infty}\left\{n-\sqrt{n^2-4 n}\right\} = \lim _{n \rightarrow \infty} \frac{\left(n-\sqrt{n^2-4 n}\right)\left(n+\sqrt{n^2-4 n}\right)}{n+\sqrt{n^2-4 n}} \) \( = \lim _{n \rightarrow \infty} \frac{n^2 - (n^2-4n)}{n+\sqrt{n^2-4 n}} \)…
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