AP EAMCET · Maths · Indefinite Integration
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(A)
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The integral expression is given as, I=∫x22sinπ4+x+exdx ⇒I=∫x22sinπ4cosx+sinxcosπ4+exdx ⇒I=∫x2212cosx+12sinx+exdx Further simplifying we get, ⇒I=∫x2cosx+sinx+exdx ⇒I=∫x2(cosx+sinx)dx+∫x2exdx As we know…
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