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AP EAMCET · Maths · Application of Derivatives

The angle of intersection between the curves \(y^2+x^2=a^2 \sqrt{2}\) and \(x^2-y^2=a^2\) is

  1. A \(\frac{\pi}{3}\)
  2. B \(\frac{\pi}{4}\)
  3. C \(\frac{\pi}{6}\)
  4. D \(\frac{\pi}{12}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{\pi}{4}\)

Step-by-step Solution

Detailed explanation

Given curves, \(y^2+x^2=a^2 \sqrt{2}\) and \(x^2-y^2=a^2\) On solving eqs. (i) and (ii), we get the point of intersection \(x=a \sqrt{\frac{\sqrt{2}+1}{2}}, y=a \sqrt{\frac{\sqrt{2}-1}{2}}\) Now, for curve \(-1: y^2+x^2=a^2 \sqrt{2}\)…