AP EAMCET · Maths · Application of Derivatives
The angle of intersection between the curves \(y^2+x^2=a^2 \sqrt{2}\) and \(x^2-y^2=a^2\) is
- A \(\frac{\pi}{3}\)
- B \(\frac{\pi}{4}\)
- C \(\frac{\pi}{6}\)
- D \(\frac{\pi}{12}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi}{4}\)
Step-by-step Solution
Detailed explanation
Given curves, \(y^2+x^2=a^2 \sqrt{2}\) and \(x^2-y^2=a^2\) On solving eqs. (i) and (ii), we get the point of intersection \(x=a \sqrt{\frac{\sqrt{2}+1}{2}}, y=a \sqrt{\frac{\sqrt{2}-1}{2}}\) Now, for curve \(-1: y^2+x^2=a^2 \sqrt{2}\)…
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