AP EAMCET · Maths · Application of Derivatives
The point on the curve \(y=x^3\), at which the tangent to the curve is parallel to the \(X\)-axis, is
- A \((2,2)\)
- B \((3,3)\)
- C \((4,4)\)
- D \((0,0)\)
Answer & Solution
Correct Answer
(D) \((0,0)\)
Step-by-step Solution
Detailed explanation
Given, curve, \(y=x^3\) \(\because\) Slope of tangent to the curve at any point \(\left(x_1, y_1\right)\) on the curve is \(=\left.\frac{d y}{d x}\right|_{\left(x_1, y_1\right)}\) So, \(\frac{d y}{d x}=3 x^2\) \(\therefore\) Slope of tangent at \(\left(x_1, y_1\right)\) is…
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