AP EAMCET · Maths · Probability
A die is thrown \((2 n+1)\) times. The probability of getting 1 or 3 or 4 atmost \(n\) times on it is
- A \(\frac{1}{n}\)
- B \(\frac{1}{2 n+1}\)
- C \(\frac{n}{2 n+4}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{2}\)
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Detailed explanation
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